Calculating the Amount of Oxygen Needed

Oct 13, 2025 by pinkandtrash.com 129 views

Understanding the Chemical Reaction

The production of Fe2O3 involves the reaction of iron (Fe) with oxygen (O2). The balanced chemical equation for this reaction is:

2Fe + 3/2O2 → Fe2O3

In this equation, 2 moles of iron react with 3/2 moles of oxygen to produce 1 mole of Fe2O3. To determine the amount of oxygen needed to produce 1.75 moles of Fe2O3, we need to use the mole ratio from the balanced equation.

Calculating the Amount of Oxygen Needed

From the balanced equation, we can see that 3/2 moles of oxygen are required to produce 1 mole of Fe2O3. To find the amount of oxygen needed to produce 1.75 moles of Fe2O3, we can multiply the amount of oxygen needed for 1 mole of Fe2O3 by 1.75.

Let's calculate the amount of oxygen needed:

Amount of oxygen needed for 1 mole of Fe2O3 = 3/2 moles Amount of oxygen needed for 1.75 moles of Fe2O3 = (3/2 moles/mole) × 1.75 moles = 2.625 moles

Converting Moles to Grams

Now that we know the amount of oxygen needed in moles, we need to convert this value to grams. The molar mass of oxygen (O2) is 32.00 g/mol. We can use this value to convert the amount of oxygen needed from moles to grams.

Let's calculate the amount of oxygen needed in grams:

Amount of oxygen needed in moles = 2.625 moles Molar mass of oxygen = 32.00 g/mol Amount of oxygen needed in grams = 2.625 moles × 32.00 g/mol = 84.00 g

Conclusion

In conclusion, to produce 1.75 moles of Fe2O3, we need 84.00 grams of oxygen. This calculation is based on the balanced chemical equation for the production of Fe2O3 and the molar mass of oxygen.

Additional Information

The balanced chemical equation for the production of Fe2O3 is: 2Fe + 3/2O2 → Fe2O3
The molar mass of oxygen (O2) is 32.00 g/mol
The amount of oxygen needed to produce 1 mole of Fe2O3 is 3/2 moles
The amount of oxygen needed to produce 1.75 moles of Fe2O3 is 2.625 moles
The amount of oxygen needed in grams is 84.00 g

References

[1] "Chemical Equations and Reactions." Chemistry LibreTexts, Libretexts, 2022, www.libretexts.org.
[2] "Molar Mass of Oxygen." Chemistry LibreTexts, Libretexts, 2022, www.libretexts.org.

Understanding Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships between reactants and products in chemical reactions. It involves the use of mole ratios to determine the amount of reactants or products required to produce a given amount of a substance.

Calculating Mole Ratios

In the balanced chemical equation for the production of Fe2O3, the mole ratio between iron (Fe) and oxygen (O2) is 2:3/2. This means that 2 moles of iron react with 3/2 moles of oxygen to produce 1 mole of Fe2O3.

To calculate the mole ratio, we can divide the number of moles of one substance by the number of moles of another substance. In this case, we can divide the number of moles of iron (2 moles) by the number of moles of oxygen (3/2 moles).

Mole ratio = 2 moles Fe / (3/2 moles O2) = 4/3

Using Mole Ratios to Calculate Amounts

We can use the mole ratio to calculate the amount of oxygen needed to produce a given amount of Fe2O3. For example, if we want to produce 1.75 moles of Fe2O3, we can use the mole ratio to calculate the amount of oxygen needed.

Let's calculate the amount of oxygen needed:

Mole ratio = 4/3 Amount of oxygen needed = (4/3) × 1.75 moles = 2.33 moles

Converting Moles to Grams

Now that we know the amount of oxygen needed in moles, we can convert this value to grams. The molar mass of oxygen (O2) is 32.00 g/mol. We can use this value to convert the amount of oxygen needed from moles to grams.

Let's calculate the amount of oxygen needed in grams:

Amount of oxygen needed in moles = 2.33 moles Molar mass of oxygen = 32.00 g/mol Amount of oxygen needed in grams = 2.33 moles × 32.00 g/mol = 74.56 g

Conclusion

In conclusion, to produce 1.75 moles of Fe2O3, we need 74.56 grams of oxygen. This calculation is based on the balanced chemical equation for the production of Fe2O3 and the molar mass of oxygen.

Additional Information

The balanced chemical equation for the production of Fe2O3 is: 2Fe + 3/2O2 → Fe2O3
The molar mass of oxygen (O2) is 32.00 g/mol
The mole ratio between iron (Fe) and oxygen (O2) is 2:3/2
The amount of oxygen needed to produce 1.75 moles of Fe2O3 is 2.33 moles
The amount of oxygen needed in grams is 74.56 g

References

[1] "Chemical Equations and Reactions." Chemistry LibreTexts, Libretexts, 2022, www.libretexts.org.
[2] "Molar Mass of Oxygen." Chemistry LibreTexts, Libretexts, 2022, www.libretexts.org.

Understanding Stoichiometry

Calculating Mole Ratios

Mole ratio = 2 moles Fe / (3/2 moles O2) = 4/3

Using Mole Ratios to Calculate Amounts

Let's calculate the amount of oxygen needed:

Mole ratio = 4/3 Amount of oxygen needed = (4/3) × 1.75 moles = 2.33 moles

Converting Moles to Grams

Let's calculate the amount of oxygen needed in grams:

Amount of oxygen needed in moles = 2.33 moles Molar mass of oxygen = 32.00 g/mol Amount of oxygen needed in grams = 2.33 moles × 32.00 g/mol = 74.56 g

Conclusion

In conclusion, to produce 1.75 moles of Fe2O3, we need 74.56 grams of oxygen. This calculation is based on the balanced chemical equation for the production of Fe2O3 and the molar mass of oxygen.

Additional Information

The balanced chemical equation for the production of Fe2O3 is: 2Fe + 3/2O2 → Fe2O3
The molar mass of oxygen (O2) is 32.00 g/mol
The mole ratio between iron (Fe) and oxygen (O2
Q&A: If 1.75 mol of Fe2O3 are produced, how many grams of oxygen are needed? ====================================================================

Q: What is the balanced chemical equation for the production of Fe2O3?

A: The balanced chemical equation for the production of Fe2O3 is: 2Fe + 3/2O2 → Fe2O3.

Q: What is the molar mass of oxygen (O2)?

A: The molar mass of oxygen (O2) is 32.00 g/mol.

Q: How many moles of oxygen are needed to produce 1 mole of Fe2O3?

A: From the balanced chemical equation, we can see that 3/2 moles of oxygen are required to produce 1 mole of Fe2O3.

Q: How many moles of oxygen are needed to produce 1.75 moles of Fe2O3?

A: To find the amount of oxygen needed to produce 1.75 moles of Fe2O3, we can multiply the amount of oxygen needed for 1 mole of Fe2O3 by 1.75.

Let's calculate the amount of oxygen needed:

Amount of oxygen needed for 1 mole of Fe2O3 = 3/2 moles Amount of oxygen needed for 1.75 moles of Fe2O3 = (3/2 moles/mole) × 1.75 moles = 2.625 moles

Q: How many grams of oxygen are needed to produce 1.75 moles of Fe2O3?

A: Now that we know the amount of oxygen needed in moles, we can convert this value to grams. We can use the molar mass of oxygen (32.00 g/mol) to convert the amount of oxygen needed from moles to grams.

Let's calculate the amount of oxygen needed in grams:

Amount of oxygen needed in moles = 2.625 moles Molar mass of oxygen = 32.00 g/mol Amount of oxygen needed in grams = 2.625 moles × 32.00 g/mol = 84.00 g

Q: What is the mole ratio between iron (Fe) and oxygen (O2) in the balanced chemical equation for the production of Fe2O3?

A: The mole ratio between iron (Fe) and oxygen (O2) in the balanced chemical equation for the production of Fe2O3 is 2:3/2.

Q: How can we use the mole ratio to calculate the amount of oxygen needed to produce a given amount of Fe2O3?

A: We can use the mole ratio to calculate the amount of oxygen needed to produce a given amount of Fe2O3 by dividing the number of moles of iron by the number of moles of oxygen.

Let's calculate the amount of oxygen needed:

Mole ratio = 2 moles Fe / (3/2 moles O2) = 4/3 Amount of oxygen needed = (4/3) × 1.75 moles = 2.33 moles

Q: How many grams of oxygen are needed to produce 1.75 moles of Fe2O3 using the mole ratio?

Let's calculate the amount of oxygen needed in grams:

Amount of oxygen needed in moles = 2.33 moles Molar mass of oxygen = 32.00 g/mol Amount of oxygen needed in grams = 2.33 moles × 32.00 g/mol = 74.56 g

Conclusion

In conclusion, to produce 1.75 moles of Fe2O3, we need 74.56 grams of oxygen. This calculation is based on the balanced chemical equation for the production of Fe2O3 and the molar mass of oxygen.

Additional Information

The balanced chemical equation for the production of Fe2O3 is: 2Fe + 3/2O2 → Fe2O3
The molar mass of oxygen (O2) is 32.00 g/mol
The mole ratio between iron (Fe) and oxygen (O2) is 2:3/2
The amount of oxygen needed to produce 1.75 moles of Fe2O3 is 2.33 moles
The amount of oxygen needed in grams is 74.56 g

References

[1] "Chemical Equations and Reactions." Chemistry LibreTexts, Libretexts, 2022, www.libretexts.org.
[2] "Molar Mass of Oxygen." Chemistry LibreTexts, Libretexts, 2022, www.libretexts.org.