Identifying the Missing Operation

Oct 13, 2025 by pinkandtrash.com 95 views

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The given equation is $\div 15 \times 15 = 480$ . However, there seems to be a missing component or operation before the division symbol. To accurately solve the equation, we need to identify the missing operation and complete the equation.

Identifying the Missing Operation

Upon closer inspection, it appears that the equation is missing a multiplication operation before the division symbol. The correct equation should be $\frac{15 \times 15}{x} = 480$ , where $x$ is the missing component.

Understanding the Equation

The equation $\frac{15 \times 15}{x} = 480$ involves a division operation, where the dividend is the product of 15 and 15, and the divisor is the variable $x$ . The equation states that the result of this division operation is equal to 480.

Solving for x

To solve for $x$ , we need to isolate the variable on one side of the equation. We can start by multiplying both sides of the equation by $x$ to eliminate the division operation.

$\frac{15 \times 15}{x} \times x = 480 \times x$

This simplifies to:

$15 \times 15 = 480x$

Next, we can divide both sides of the equation by 480 to solve for $x$ .

$\frac{15 \times 15}{480} = x$

Calculating the Value of x

To calculate the value of $x$ , we need to evaluate the expression $\frac{15 \times 15}{480}$ .

$15 \times 15 = 225$

$\frac{225}{480} = 0.46875$

Therefore, the value of $x$ is 0.46875.

Conclusion

In conclusion, the given equation $\div 15 \times 15 = 480$ is incomplete and requires a missing operation to be accurately solved. By identifying the missing operation and completing the equation, we can solve for the variable $x$ . The value of $x$ is 0.46875.

Frequently Asked Questions

What is the missing operation in the given equation? The missing operation is a multiplication operation before the division symbol.
How do we solve for x in the equation? We can solve for x by multiplying both sides of the equation by x, then dividing both sides by 480.
What is the value of x? The value of x is 0.46875.

Q: What is the missing operation in the given equation?

A: The missing operation in the given equation is a multiplication operation before the division symbol. The correct equation should be $\frac{15 \times 15}{x} = 480$ .

Q: How do we solve for x in the equation?

A: To solve for x, we can multiply both sides of the equation by x to eliminate the division operation. This simplifies the equation to $15 \times 15 = 480x$ . We can then divide both sides of the equation by 480 to solve for x.

Q: What is the value of x?

A: The value of x is 0.46875.

Q: Can you explain the concept of division operations in more detail?

A: Division operations involve dividing a number by another number to find the quotient. In the equation $\frac{15 \times 15}{x} = 480$ , we are dividing the product of 15 and 15 by x to find the quotient, which is equal to 480.

Q: How do we identify missing operations in equations?

A: To identify missing operations in equations, we need to carefully read and analyze the equation. In the given equation, we noticed that the division symbol was not preceded by a multiplication operation. By adding the missing operation, we were able to complete the equation and solve for x.

Q: What are some common mistakes to avoid when solving equations?

A: Some common mistakes to avoid when solving equations include:

Not identifying missing operations
Not following the order of operations (PEMDAS)
Not isolating the variable on one side of the equation
Not checking the solution for accuracy

Q: How do we check the solution for accuracy?

A: To check the solution for accuracy, we can substitute the value of x back into the original equation and verify that it is true. In this case, we can substitute x = 0.46875 into the equation $\frac{15 \times 15}{x} = 480$ and verify that it is equal to 480.

Q: What are some real-world applications of solving equations?

A: Solving equations has many real-world applications, including:

Calculating the cost of goods and services
Determining the amount of time it takes to complete a task
Finding the area and perimeter of shapes
Solving problems in physics, engineering, and other fields