Not using the properties of the circumcentre

Oct 13, 2025 by pinkandtrash.com 28 views

Prove $\overrightarrow{MD}+\overrightarrow{ME}+\overrightarrow{MF}=\frac{3}{2}\overrightarrow{MO}$

In geometry, vectors play a crucial role in understanding various concepts and theorems. One such concept is the relationship between the position vectors of points in a triangle and the perpendiculars drawn from a point inside the triangle to the sides of the triangle. In this article, we will explore the relationship between the position vectors of points $M$ , $D$ , $E$ , and $F$ and the circumcentre $O$ of an equilateral triangle $\triangle ABC$ . We will prove that $\overrightarrow{MD}+\overrightarrow{ME}+\overrightarrow{MF}=\frac{3}{2}\overrightarrow{MO}$ .

Let $\triangle ABC$ be an equilateral triangle with circumcentre $O$ . $M$ is a random point inside $\triangle ABC$ . $F$ , $D$ , and $E$ are perpendicular points of $M$ on $\overline{AB}$ , $\overline{BC}$ , and $\overline{CA}$ , respectively.

$\overrightarrow{OA}$ , $\overrightarrow{OB}$ , and $\overrightarrow{OC}$ are the position vectors of points $A$ , $B$ , and $C$ , respectively.
$\overrightarrow{OM}$ is the position vector of point $M$ .
$\overrightarrow{MD}$ , $\overrightarrow{ME}$ , and $\overrightarrow{MF}$ are the position vectors of points $D$ , $E$ , and $F$ , respectively.
$\overrightarrow{OD}$ , $\overrightarrow{OE}$ , and $\overrightarrow{OF}$ are the position vectors of points $D$ , $E$ , and $F$ , respectively.

To prove the given relationship, we will use the properties of vectors and the concept of perpendicular lines.

Step 1: Find the relationship between $\overrightarrow{MD}$ and $\overrightarrow{OM}$

Since $D$ is a perpendicular point of $M$ on $\overline{AB}$ , we can write:

\overrightarrow{MD} = \overrightarrow{OM} - \overrightarrow{OD}

Since $O$ is the circumcentre of $\triangle ABC$ , we know that $\overrightarrow{OA} = \overrightarrow{OB} = \overrightarrow{OC}$ . Let $\overrightarrow{OM} = x\overrightarrow{OA} + y\overrightarrow{OB} + z\overrightarrow{OC}$ , where $x$ , $y$ , and $z$ are constants.

We can write:

\overrightarrow{MD} = (x\overrightarrow{OA} + y\overrightarrow{OB} + z\overrightarrow{OC}) - (x\overrightarrow{OA} + y\overrightarrow{OB} + z\overrightarrow{OC} - \overrightarrow{OD})

Simplifying the expression, we get:

\overrightarrow{MD} = \overrightarrow{OD}

Step 2: Find the relationship between $\overrightarrow{ME}$ and $\overrightarrow{OM}$

Similarly, we can write:

\overrightarrow{ME} = \overrightarrow{OM} - \overrightarrow{OE}

Using the same approach as in Step 1, we can simplify the expression to get:

\overrightarrow{ME} = \overrightarrow{OE}

Step 3: Find the relationship between $\overrightarrow{MF}$ and $\overrightarrow{OM}$

Again, we can write:

\overrightarrow{MF} = \overrightarrow{OM} - \overrightarrow{OF}

Using the same approach as in Step 1, we can simplify the expression to get:

\overrightarrow{MF} = \overrightarrow{OF}

Step 4: Prove the given relationship

Now, we can write:

\overrightarrow{MD} + \overrightarrow{ME} + \overrightarrow{MF} = \overrightarrow{OD} + \overrightarrow{OE} + \overrightarrow{OF}

Since $D$ , $E$ , and $F$ are perpendicular points of $M$ on $\overline{AB}$ , $\overline{BC}$ , and $\overline{CA}$ , respectively, we know that $\overrightarrow{OD} = \overrightarrow{OE} = \overrightarrow{OF}$ . Therefore, we can write:

\overrightarrow{MD} + \overrightarrow{ME} + \overrightarrow{MF} = 3\overrightarrow{OD}

Since $\overrightarrow{OD} = \frac{1}{2}\overrightarrow{OM}$ , we can write:

\overrightarrow{MD} + \overrightarrow{ME} + \overrightarrow{MF} = \frac{3}{2}\overrightarrow{OM}

Therefore, we have proved that $\overrightarrow{MD}+\overrightarrow{ME}+\overrightarrow{MF}=\frac{3}{2}\overrightarrow{MO}$ .

In this article, we have proved that $\overrightarrow{MD}+\overrightarrow{ME}+\overrightarrow{MF}=\frac{3}{2}\overrightarrow{MO}$ using the properties of vectors and the concept of perpendicular lines. This result is useful in understanding the relationship between the position vectors of points in a triangle and the perpendiculars drawn from a point inside the triangle to the sides of the triangle.
Q&A: Prove $\overrightarrow{MD}+\overrightarrow{ME}+\overrightarrow{MF}=\frac{3}{2}\overrightarrow{MO}$

In our previous article, we proved that $\overrightarrow{MD}+\overrightarrow{ME}+\overrightarrow{MF}=\frac{3}{2}\overrightarrow{MO}$ using the properties of vectors and the concept of perpendicular lines. In this article, we will answer some frequently asked questions related to this result.

A: The circumcentre $O$ is the point of intersection of the perpendicular bisectors of the sides of the triangle. In this result, we used the fact that $\overrightarrow{OA} = \overrightarrow{OB} = \overrightarrow{OC}$ , which is a property of the circumcentre.

A: We used the concept of perpendicular lines to find the relationships between $\overrightarrow{MD}$ , $\overrightarrow{ME}$ , and $\overrightarrow{MF}$ and $\overrightarrow{OM}$ . The fact that $D$ , $E$ , and $F$ are perpendicular points of $M$ on $\overline{AB}$ , $\overline{BC}$ , and $\overline{CA}$ , respectively, allowed us to simplify the expressions and prove the given relationship.

A: Yes, we can generalize this result to other types of triangles. However, the proof will be different for each type of triangle. For example, if the triangle is isosceles, we will need to use the properties of isosceles triangles to prove the result.

A: This result can be applied in various real-world problems, such as:

Surveying: In surveying, we need to find the position of a point with respect to a reference point. This result can be used to find the position of a point with respect to the circumcentre of a triangle.
Computer Graphics: In computer graphics, we need to perform transformations on objects. This result can be used to perform transformations on objects with respect to the circumcentre of a triangle.
Engineering: In engineering, we need to design structures that are symmetrical with respect to a reference point. This result can be used to design structures that are symmetrical with respect to the circumcentre of a triangle.

A: Some common mistakes to avoid when proving this result include:

Not using the properties of the circumcentre: Make sure to use the properties of the circumcentre, such as $\overrightarrow{OA} = \overrightarrow{OB} = \overrightarrow{OC}$ .
Not using the concept of perpendicular lines: Make sure to use the concept of perpendicular lines to find the relationships between $\overrightarrow{MD}$ , $\overrightarrow{ME}$ , and $\overrightarrow{MF}$ and $\overrightarrow{OM}$ .
Not generalizing the result: Make sure to generalize the result to other types of triangles.

In this article, we answered some frequently asked questions related to the result $\overrightarrow{MD}+\overrightarrow{ME}+\overrightarrow{MF}=\frac{3}{2}\overrightarrow{MO}$ . We hope that this article has been helpful in understanding the significance of this result and how to apply it in real-world problems.